I need to extract the string between the "" after the "user" string in the following string
{ "Response":"ok","pin":"1234567","user":"goldriver" }
I found looking on an online regex tester and debugger that (?:[^"]*"){11}\K[^"]* worked but I tried to port it in my scipt and I have errors reported:
Dim regex As Regex = New Regex((?:[^"]*"){11}\K[^"]*)
I guess the regex expression I found is not supported in VB script
anyome can help with this ?
thanks
{ "Response":"ok","pin":"1234567","user":"goldriver" }
I found looking on an online regex tester and debugger that (?:[^"]*"){11}\K[^"]* worked but I tried to port it in my scipt and I have errors reported:
Dim regex As Regex = New Regex((?:[^"]*"){11}\K[^"]*)
I guess the regex expression I found is not supported in VB script
anyome can help with this ?
thanks
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